Optimal. Leaf size=86 \[ \frac{\sqrt [3]{1+i \tan (c+d x)} \tan ^{m+1}(c+d x) F_1\left (m+1;\frac{7}{3},1;m+2;-i \tan (c+d x),i \tan (c+d x)\right )}{a d (m+1) \sqrt [3]{a+i a \tan (c+d x)}} \]
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Rubi [A] time = 0.114951, antiderivative size = 86, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.115, Rules used = {3564, 135, 133} \[ \frac{\sqrt [3]{1+i \tan (c+d x)} \tan ^{m+1}(c+d x) F_1\left (m+1;\frac{7}{3},1;m+2;-i \tan (c+d x),i \tan (c+d x)\right )}{a d (m+1) \sqrt [3]{a+i a \tan (c+d x)}} \]
Antiderivative was successfully verified.
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Rule 3564
Rule 135
Rule 133
Rubi steps
\begin{align*} \int \frac{\tan ^m(c+d x)}{(a+i a \tan (c+d x))^{4/3}} \, dx &=\frac{\left (i a^2\right ) \operatorname{Subst}\left (\int \frac{\left (-\frac{i x}{a}\right )^m}{(a+x)^{7/3} \left (-a^2+a x\right )} \, dx,x,i a \tan (c+d x)\right )}{d}\\ &=\frac{\left (i \sqrt [3]{1+i \tan (c+d x)}\right ) \operatorname{Subst}\left (\int \frac{\left (-\frac{i x}{a}\right )^m}{\left (1+\frac{x}{a}\right )^{7/3} \left (-a^2+a x\right )} \, dx,x,i a \tan (c+d x)\right )}{d \sqrt [3]{a+i a \tan (c+d x)}}\\ &=\frac{F_1\left (1+m;\frac{7}{3},1;2+m;-i \tan (c+d x),i \tan (c+d x)\right ) \sqrt [3]{1+i \tan (c+d x)} \tan ^{1+m}(c+d x)}{a d (1+m) \sqrt [3]{a+i a \tan (c+d x)}}\\ \end{align*}
Mathematica [F] time = 33.4989, size = 0, normalized size = 0. \[ \int \frac{\tan ^m(c+d x)}{(a+i a \tan (c+d x))^{4/3}} \, dx \]
Verification is Not applicable to the result.
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Maple [F] time = 0.148, size = 0, normalized size = 0. \begin{align*} \int{ \left ( \tan \left ( dx+c \right ) \right ) ^{m} \left ( a+ia\tan \left ( dx+c \right ) \right ) ^{-{\frac{4}{3}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RuntimeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{2^{\frac{2}{3}} \left (\frac{-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}\right )^{m} \left (\frac{a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}\right )^{\frac{2}{3}}{\left (e^{\left (4 i \, d x + 4 i \, c\right )} + 2 \, e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right )} e^{\left (-\frac{8}{3} i \, d x - \frac{8}{3} i \, c\right )}}{4 \, a^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\tan ^{m}{\left (c + d x \right )}}{\left (a \left (i \tan{\left (c + d x \right )} + 1\right )\right )^{\frac{4}{3}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\tan \left (d x + c\right )^{m}}{{\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac{4}{3}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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